分享PHP计算两个日期相差天数的代码

发布:smiling　来源: PHP粉丝网　添加日期：2021-07-01 10:15:33　浏览: 评论：0　

这篇文章主要为大家分享了PHP计算两个日期差的代码，实例分析了php操作日期的技巧,需要的朋友可以参考下，本文实例讲述了php计算两个日期相差天数的方法，分享给大家供大家参考，具体实现方法如下：

<?php

$date1 = date( 'Y-m-d' );

$date2 = "2015-12-04";

$diff = abs(strtotime($date2) - strtotime($date1));

$years = floor($diff / (365*60*60*24));

$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));

$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

printf("%d years, %d months, %d days\n", $years, $months, $days);

-------------------------------------------------------- OR

$date1 = new DateTime("2007-03-24");

$date2 = new DateTime("2009-06-26");

$interval = $date1->diff($date2);

echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";

// shows the total amount of days (not divided into years, months and days like above)

echo "difference " . $interval->days . " days ";

-------------------------------------------------------- OR



/**

* Calculate differences between two dates with precise semantics. Based on PHPs DateTime::diff()

* implementation by Derick Rethans. Ported to PHP by Emil H, 2011-05-02. No rights reserved.

*/

function _date_range_limit($start, $end, $adj, $a, $b, $result)

{

if ($result[$a] < $start) {

  $result[$b] -= intval(($start - $result[$a] - 1) / $adj) + 1;

  $result[$a] += $adj * intval(($start - $result[$a] - 1) / $adj + 1);

}

if ($result[$a] >= $end) {

  $result[$b] += intval($result[$a] / $adj);

  $result[$a] -= $adj * intval($result[$a] / $adj);

}

return $result;

}

function _date_range_limit_days($base, $result)

{

$days_in_month_leap = array(31, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);

$days_in_month = array(31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);

_date_range_limit(1, 13, 12, "m", "y", &$base);

$year = $base["y"];

$month = $base["m"];

if (!$result["invert"]) {

  while ($result["d"] < 0) {

   $month--;

   if ($month < 1) {

    $month += 12;

    $year--;

   }

   $leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);

   $days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];

   $result["d"] += $days;

   $result["m"]--;

  }

} else {

  while ($result["d"] < 0) {

   $leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);

   $days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];

   $result["d"] += $days;

   $result["m"]--;

   $month++;

   if ($month > 12) {

    $month -= 12;

    $year++;

   }

  }

}

return $result;

}

function _date_normalize($base, $result)

{

$result = _date_range_limit(0, 60, 60, "s", "i", $result);

$result = _date_range_limit(0, 60, 60, "i", "h", $result);

$result = _date_range_limit(0, 24, 24, "h", "d", $result);

$result = _date_range_limit(0, 12, 12, "m", "y", $result);

$result = _date_range_limit_days(&$base, &$result);

$result = _date_range_limit(0, 12, 12, "m", "y", $result);

return $result;

}

/**

* Accepts two unix timestamps.

*/

function _date_diff($one, $two)

{

$invert = false;

if ($one > $two) {

  list($one, $two) = array($two, $one);

  $invert = true;

}

$key = array("y", "m", "d", "h", "i", "s");

$a = array_combine($key, array_map("intval", explode(" ", date("Y m d H i s", $one))));

$b = array_combine($key, array_map("intval", explode(" ", date("Y m d H i s", $two))));

$result = array();

$result["y"] = $b["y"] - $a["y"];

$result["m"] = $b["m"] - $a["m"];

$result["d"] = $b["d"] - $a["d"];

$result["h"] = $b["h"] - $a["h"];

$result["i"] = $b["i"] - $a["i"];

$result["s"] = $b["s"] - $a["s"];

$result["invert"] = $invert ? 1 : 0;

$result["days"] = intval(abs(($one - $two)/86400));

if ($invert) {

  _date_normalize(&$a, &$result);

} else {

  _date_normalize(&$b, &$result);

}

return $result;

}

$date = "2014-12-04 19:37:22";

echo '<pre>';

print_r( _date_diff( strtotime($date), time() ) );

echo '</pre>';

?>